a^(u(x)) > a^(v(x)), a > 1
Same base, base greater than 1
Keep the inequality direction and solve u(x) > v(x).
2^(x + 1) > 8 becomes x + 1 > 3.
Solve exponential inequalities like 2^(x+1) > 8 — see exactly when the inequality sign flips based on the base.
What this page explains
Calculator
Same-base problems compare exponents. Different-base problems use logs first.
Current problem
Answer
Interval notation
Rewrite the constant side as a power of base 0.5 before comparing exponents.
Since 0 < 0.5 < 1, the exponential function is decreasing. Larger exponents make smaller values, so the inequality sign flips.
Subtract the right exponent from the left exponent, then isolate x.
The final boundary becomes the endpoint of the interval. Strict symbols use parentheses; inclusive symbols use brackets.
Exponential Inequality Graph
Left curve
0.5^(x)
Right curve
0.5^(-2)
Solution
The solution is x ≥ -2.
Number Line
Drag to pan. Use the controls or mouse wheel to zoom the view.
Interactive Flip Rule
The only mystery is whether a^x is increasing or decreasing. When the base slides below 1, the curve falls as x grows, so same-base inequalities reverse.
Base is between 0 and 1 -> inequality FLIPS
0.5^3 < 0.5^1, even though 3 > 1. The curve is decreasing, so the value comparison points the other way.
Step-by-Step Breakdown
If a > 1, keep the sign. If 0 < a < 1, the function decreases, so flip the sign before solving the exponent inequality.
The exponents cannot be compared directly. Logs convert the problem into a linear inequality while preserving the comparison.
Method Selector
a^(u(x)) > a^(v(x)), a > 1
Keep the inequality direction and solve u(x) > v(x).
2^(x + 1) > 8 becomes x + 1 > 3.
a^(u(x)) > a^(v(x)), 0 < a < 1
Flip the inequality direction because the exponential function is decreasing.
(1/2)^x <= (1/2)^(-2) becomes x >= -2.
a^(u(x)) > b^(v(x))
Use logarithms, collect x terms, then solve the resulting linear inequality.
3^x > 2^(x + 1) becomes x ln(3) > (x + 1) ln(2).
a^x compared with a negative number
Use the fact that valid exponential outputs are always positive.
3^x > -7 is true for every real x.
Avoid These Mistakes
Comparing exponents when the bases are different
Only compare exponents directly after rewriting both sides with the same positive base.
Forgetting the fractional-base flip
When 0 < base < 1, the function decreases, so the inequality direction reverses.
Taking logs of a nonpositive side
Handle range cases first. If the right side is negative, many exponential comparisons are automatically true or false.
Examples
Base greater than 1
Rewrite 8 as 2^3, keep the sign because base 2 is increasing, then solve x + 1 > 3.
Base between 0 and 1
Rewrite 4 as (1/2)^(-2), then flip <= to >= because base 0.5 is decreasing.
Sign flipped because 0 < base < 1.
Always true range case
Since 3^x is always positive, it is automatically greater than -7 for every real x.
FAQ
First try to rewrite both sides with the same base. Then compare the exponents, keeping the inequality direction when the base is greater than 1 and flipping it when the base is between 0 and 1.
If 0 < a < 1, the function a^x is decreasing. Larger exponents create smaller values, so a comparison such as (1/2)^x <= (1/2)^(-2) becomes x >= -2.
An exponential equation looks for exact crossing points where two expressions are equal. An exponential inequality asks where one expression is greater or less, so the final answer is usually an interval.
Yes. Because a^x is always positive for valid real exponential bases, an inequality such as 2^x < 0 has no real solution. An inequality such as 2^x > -5 is true for all real numbers.
If the bases cannot be matched as powers of one common base, take natural logs on both sides, use the power rule, collect x terms, and solve the resulting linear inequality.
Use logarithms. This page shows the log-conversion path for different-base inputs, and the logarithmic inequality calculator covers the related log-specific rules.
No. Direct exponent comparison only works after both sides are rewritten with the same base. If the bases cannot be matched, use logarithms or a graph-supported numeric comparison.
For valid positive bases other than 1, a^x is always positive. That means an inequality such as 3^x > -7 is true for all real x, while 3^x < -7 has no real solution.